二元一次方程组计算题1.13X+1.17Y=71169.60.13X+0.17Y=6648.51
2019-04-13
二元一次方程组计算题
1.13X+1.17Y=71169.6
0.13X+0.17Y=6648.51
优质解答
1.13X+1.17Y=71169.6.(1)
0.13X+0.17Y=6648.51.(2)
(1)-(2),得
X+Y=64521.09
Y=64521.09-X
代入(2),得
0.13X+0.17(64521.09-X)=6648.51
X=108001.88
Y=-43480.79
1.13X+1.17Y=71169.6.(1)
0.13X+0.17Y=6648.51.(2)
(1)-(2),得
X+Y=64521.09
Y=64521.09-X
代入(2),得
0.13X+0.17(64521.09-X)=6648.51
X=108001.88
Y=-43480.79