数学
数学难题计算:3(2x-1)(x-3)-(3-2x)(4x+1)(a+b)(a-b)^2(b-a)^3(-a-b)^4(结果表示成幂的形式)(x+2y)^2-(x-2y-2)(x-2y+2)

2019-06-25

数学难题
计算:
3(2x-1)(x-3)-(3-2x)(4x+1)
(a+b)(a-b)^2(b-a)^3(-a-b)^4(结果表示成幂的形式)
(x+2y)^2-(x-2y-2)(x-2y+2)
优质解答
计算:
3(2x-1)(x-3)-(3-2x)(4x+1)
=3(2x^2-6x-x+3)-(12x+3-8x^2-2x)
=6x^2-21x+9+8x^2-10x-3
=14x^2-31x+6
(a+b)(a-b)^2(b-a)^3(-a-b)^4(结果表示成幂的形式)
=(a+b)(a-b)^2[-(a-b)^3](a+b)^4
=-(a+b)^5(a-b)^5
(x+2y)^2-(x-2y-2)(x-2y+2)
=(x+2y)^2-[(x-2y)^2-4]
=x^2+4xy+4y^2-x^2+4xy-4y^2+4
=8xy+4
计算:
3(2x-1)(x-3)-(3-2x)(4x+1)
=3(2x^2-6x-x+3)-(12x+3-8x^2-2x)
=6x^2-21x+9+8x^2-10x-3
=14x^2-31x+6
(a+b)(a-b)^2(b-a)^3(-a-b)^4(结果表示成幂的形式)
=(a+b)(a-b)^2[-(a-b)^3](a+b)^4
=-(a+b)^5(a-b)^5
(x+2y)^2-(x-2y-2)(x-2y+2)
=(x+2y)^2-[(x-2y)^2-4]
=x^2+4xy+4y^2-x^2+4xy-4y^2+4
=8xy+4
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