4x - 3y =15
4x + 10y =28
两式相减可得13y = 13 ,得y = 1
将y = 1带入任意一式解得 x = 4.5
所以原方程组的解为 x = 4.5,y = 1 4x - 3y =15
4x + 10y =28
两式相减可得13y = 13 ,得y = 1
将y = 1带入任意一式解得 x = 4.5
所以原方程组的解为 x = 4.5,y = 1