解二元一次方程组 (1) x+1=5(y+2) 3(2x-5)-4(3y+4)=5 (2)y/3-x+1/6=3 2(x-y/2)=3(x+y/18)详细过程
2019-04-13
解二元一次方程组 (1) x+1=5(y+2) 3(2x-5)-4(3y+4)=5 (2)y/3-x+1/6=3 2(x-y/2)=3(x+y/18)
详细过程
优质解答
(1) x+1=5(y+2)
x+1=5y+10
x=5y+9
3(2x-5)-4(3y+4)=5
6x-15-12y-16=5
6(5y+9)-15-12y-16=5
30y-12y=-18
18y=18
y=1
x=14
(1) x+1=5(y+2)
x+1=5y+10
x=5y+9
3(2x-5)-4(3y+4)=5
6x-15-12y-16=5
6(5y+9)-15-12y-16=5
30y-12y=-18
18y=18
y=1
x=14