数学
20道代数题,30道几何题,

2019-04-12

20道代数题,30道几何题,
优质解答
1.满足n^3+100能被n+10整除的最大正整数n=______.
n^3+100
=n^3+1000-900
=(n+10)*(n^2-10n+100)-900
∴如果(n+10)|(n^3+100)
那么:(n+10)|900
∴n+10
1.满足n^3+100能被n+10整除的最大正整数n=______.
n^3+100
=n^3+1000-900
=(n+10)*(n^2-10n+100)-900
∴如果(n+10)|(n^3+100)
那么:(n+10)|900
∴n+10
相关问答