数学
二元一次方程分式怎么解?题目是x-y/3=x+y/2+1 2x-5y=9

2019-05-28

二元一次方程分式怎么解?题目是x-y/3=x+y/2+1 2x-5y=9
优质解答
x-y/3=x+y/2+1
2(x-y)=3(x+y)+6
2x-2y=3x+3y+6
-x-5y=6x
x+5y=-6
x=-6-5y
把x=-6-5y代入2x-5y=9
2(-6-5y)-5y=9
-12-10y-5y=9
-15y=21
y=-7/5
把y=-7/5代入x=-6-5y
x=1
所以y=-7/5,x=1
题目是x-y/3=x+y/2+1 2x-5y=9还是x-y/3=x+y/(2+1) 2x-5y=9?我的是x-y/3=x+y/2+1 2x-5y=9
x-y/3=x+y/2+1
2(x-y)=3(x+y)+6
2x-2y=3x+3y+6
-x-5y=6x
x+5y=-6
x=-6-5y
把x=-6-5y代入2x-5y=9
2(-6-5y)-5y=9
-12-10y-5y=9
-15y=21
y=-7/5
把y=-7/5代入x=-6-5y
x=1
所以y=-7/5,x=1
题目是x-y/3=x+y/2+1 2x-5y=9还是x-y/3=x+y/(2+1) 2x-5y=9?我的是x-y/3=x+y/2+1 2x-5y=9
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