优质解答
对于a*x^2+b*x+c=0.
用公式(a*x^2-c)/(2*a*x+b)进行估算,重复迭代即可.
2*x^2+3*x-7 = 0
开始时,令x=2,则:
0,2
1,1.363636364
2,1.267839688
3,1.265565720
4,1.265564437
5,1.265564437
6,1.265564437
7,1.265564437
8,1.265564437
9,1.265564437
10,1.265564437
开始时,令x=-2,则:
0,-2
1,-3.
2,-2.777777778
3,-2.765601219
4,-2.765564437
5,-2.765564436
6,-2.765564439
7,-2.765564435
8,-2.765564437
9,-2.765564436
10,-2.765564439
对于a*x^2+b*x+c=0.
用公式(a*x^2-c)/(2*a*x+b)进行估算,重复迭代即可.
2*x^2+3*x-7 = 0
开始时,令x=2,则:
0,2
1,1.363636364
2,1.267839688
3,1.265565720
4,1.265564437
5,1.265564437
6,1.265564437
7,1.265564437
8,1.265564437
9,1.265564437
10,1.265564437
开始时,令x=-2,则:
0,-2
1,-3.
2,-2.777777778
3,-2.765601219
4,-2.765564437
5,-2.765564436
6,-2.765564439
7,-2.765564435
8,-2.765564437
9,-2.765564436
10,-2.765564439