数学
跪求初三上二次根式计算题50道加减乘除都可以

2019-05-23

跪求初三上二次根式计算题50道
加减乘除都可以
优质解答
1.3√(1/6)-4√(50)+30√(2/3)
答案3√(1/6)-4√(50)+30√(2/3)
= 3×√6/6-4×5√2+30×√6/3
=√6/2-20√2+10√6
2.(1-根号2)/2乘以(1+根号2)/2
题是这样的二分之一减根号2乘以二分之一加根号2
答案:(1-根号2)/2乘以(1+根号2)/2
=(1-√2)*(1-√2)/4
=(1-2)/4
=-1/4
3.√(1/2x)^2+10/9x^2
√[(1/2x)^2+10/9x^2]
=√(x^2/4+10x^2/9)
=√(9x^2/36+40x^2/36)
=√(49x^2/36)
=7|x|/6;
4.√a^4mb^2n+1(a、b为正数)
[√(a^4mb^2n)]+1(a、b为正数)
=a^2mb^n+1;
5.√(4a^5+8a^4)(a^2+3a+2)(a>=0)
√[(4a^5+8a^4)(a^2+3a+2)](a>=0)
=√[4a^4(a+2)(a+2)(a+1)]
=√[(2a^2)^2(a+2)^2(a+1)]
=2a^2(a+2)√(a+1).
50道太多了呀,只能这样了,我还有事
1.3√(1/6)-4√(50)+30√(2/3)
答案3√(1/6)-4√(50)+30√(2/3)
= 3×√6/6-4×5√2+30×√6/3
=√6/2-20√2+10√6
2.(1-根号2)/2乘以(1+根号2)/2
题是这样的二分之一减根号2乘以二分之一加根号2
答案:(1-根号2)/2乘以(1+根号2)/2
=(1-√2)*(1-√2)/4
=(1-2)/4
=-1/4
3.√(1/2x)^2+10/9x^2
√[(1/2x)^2+10/9x^2]
=√(x^2/4+10x^2/9)
=√(9x^2/36+40x^2/36)
=√(49x^2/36)
=7|x|/6;
4.√a^4mb^2n+1(a、b为正数)
[√(a^4mb^2n)]+1(a、b为正数)
=a^2mb^n+1;
5.√(4a^5+8a^4)(a^2+3a+2)(a>=0)
√[(4a^5+8a^4)(a^2+3a+2)](a>=0)
=√[4a^4(a+2)(a+2)(a+1)]
=√[(2a^2)^2(a+2)^2(a+1)]
=2a^2(a+2)√(a+1).
50道太多了呀,只能这样了,我还有事
相关问答