大哥来帮下物理质点同时参与两个在同一直线上的简谐振动,其表达式为x1= 4cos(3t+ π/6)和x2= 4cos(3t- 5π/6)求合振动的振幅和初相.
2019-06-20
大哥来帮下物理
质点同时参与两个在同一直线上的简谐振动,其表达式为x1= 4cos(3t+ π/6)和x2= 4cos(3t- 5π/6)求合振动的振幅和初相.
优质解答
x1= 4cos(3t+ π/6)和x2= 4cos(3t- 5π/6) 就是X1+X2=4[cos(3t+ π/6)+cos(3t- 5π/6)]=4[cos(3t+ π/6)+cos(3t+π/6-π)]=4[cos(3t+ π/6)-cos(3t+π/6)]=0
振幅和初相均为0
x1= 4cos(3t+ π/6)和x2= 4cos(3t- 5π/6) 就是X1+X2=4[cos(3t+ π/6)+cos(3t- 5π/6)]=4[cos(3t+ π/6)+cos(3t+π/6-π)]=4[cos(3t+ π/6)-cos(3t+π/6)]=0
振幅和初相均为0