数学题求解two adjacent five-dot sections of a ticker-tapemeasure 10 cm and 16cm ,respectively.the intervalbewteen dots is 0.02s.deduce the accelerationof the trolley which produced the tape这道题答案是6但是我用vt图画算出那个6是第二段（16cm路程）的斜率第一段的斜率比他大这是怎么回事他问题到底在问什么
2019-04-02
数学题求解
two adjacent five-dot sections of a ticker-tape
measure 10 cm and 16cm ,respectively.the interval
bewteen dots is 0.02s.deduce the acceleration
of the trolley which produced the tape
这道题答案是6
但是我用vt图画算出那个6是第二段（16cm路程）的斜率
第一段的斜率比他大
这是怎么回事
他问题到底在问什么
优质解答
two adjacent five-dot sections of a ticker-tape measure 10 cm and 16cm ,respectively.the interval between dots is 0.02s.deduce the acceleration of the trolley which produced the tape.
打点计时器求小车的加速度?
先搞清楚 打点计时器原理——纸带上每5个点的时间间隔是0.02s；计数点,每5个点为1个计数点,每两个计数点之间的时间间隔是0.1s.
于是,s=16cm-10cm=6cm=0.06m,t²=0.1²=0.01s²,则 a=s/t²=0.06/0.01=6m/s².
two adjacent five-dot sections of a ticker-tape measure 10 cm and 16cm ,respectively.the interval between dots is 0.02s.deduce the acceleration of the trolley which produced the tape.
打点计时器求小车的加速度?
先搞清楚 打点计时器原理——纸带上每5个点的时间间隔是0.02s；计数点,每5个点为1个计数点,每两个计数点之间的时间间隔是0.1s.
于是,s=16cm-10cm=6cm=0.06m,t²=0.1²=0.01s²,则 a=s/t²=0.06/0.01=6m/s².