x²-2(1+√2)x+2√2=0
[x-(1+√2)]²=(1+√2)²-2√2
[x-(1+√2)]²=3
x=1+√2±√3
x1=1+√2-√3
x2=1+√2+√3 x²-2(1+√2)x+2√2=0
[x-(1+√2)]²=(1+√2)²-2√2
[x-(1+√2)]²=3
x=1+√2±√3
x1=1+√2-√3
x2=1+√2+√3