[1/(t^2-1)]dt的原函数是什么给出具体过程,不好意思,别嫌少,呵呵
2019-04-08
[1/(t^2-1)]dt的原函数是什么给出具体过程,不好意思,别嫌少,呵呵
优质解答
[1/(t^2-1)]dt=1/2*[1/(t-1)-1/(t+1)]dt=1/2*(ln|t-1|-ln|t+1|)=1/2*ln(|t-1|/|t+1|)+C
[1/(t^2-1)]dt=1/2*[1/(t-1)-1/(t+1)]dt=1/2*(ln|t-1|-ln|t+1|)=1/2*ln(|t-1|/|t+1|)+C