数学
数学题之53用递等式计算.1.15/4*12/5-12/5/120% 2.100.1-(2.625+0.425)*303.99/{23/4-(9/5+21/5*2/7)} 4.(1/4+3/8)/(1-3/10)

2020-05-31

数学题之53
用递等式计算.
1.15/4*12/5-12/5/120% 2.100.1-(2.625+0.425)*30
3.99/{23/4-(9/5+21/5*2/7)} 4.(1/4+3/8)/(1-3/10)
优质解答
用递等式计算.1.15/4*12/5-12/5/120% =9-2 =7 2.100.1-(2.625+0.425)*30 =100.1-3.05*30 =100.1-91.5 =8.6 3.99/{23/4-(9/5+21/5*2/7)} =99/[23/4-3] =99/11/4] =36 4.(1/4+3/8)/(1-3/10) =5/8/(7/10) =25/2... 用递等式计算.1.15/4*12/5-12/5/120% =9-2 =7 2.100.1-(2.625+0.425)*30 =100.1-3.05*30 =100.1-91.5 =8.6 3.99/{23/4-(9/5+21/5*2/7)} =99/[23/4-3] =99/11/4] =36 4.(1/4+3/8)/(1-3/10) =5/8/(7/10) =25/2...
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