数学
高数∫（2y)/(y^2+1)dy怎么算?

2019-04-14

高数∫（2y)/(y^2+1)dy怎么算?
优质解答
∫（2y)/(y^2+1)dy
=∫[1/(y^2+1)]dy^2
=∫[1/(y^2+1)]d(y^2+1)
=ln(y^2+1)+C ∫（2y)/(y^2+1)dy
=∫[1/(y^2+1)]dy^2
=∫[1/(y^2+1)]d(y^2+1)
=ln(y^2+1)+C
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