优质解答
（1）∠1=(1/3) ∠ACB+∠E=(1/3) ∠ACB+(180-(2/3) ∠ABC- (2/3) ∠ACB)=130
整理得：∠ACB+2∠ABC=150 ①
∠2=(1/3) ∠ABC+∠E=(1/3) ∠ABC+(180-(2/3) ∠ABC- (2/3) ∠ACB)=110
整理得：∠ABC+2∠ACB=210 ②
由方程①②解得：∠ACB=90，∠ABC=30
∴∠A=180-∠ACB-∠ABC=180-90-30=60
（2）∵∠2=∠1+（1/3）∠ABC=110+（1/3）∠ABC=130
∴∠ABC=60
∴∠EBC=20
∴∠DCB=180-20-130=30
∴∠ACB=60
∴∠A=180-60-60=60
（1）∠1=(1/3) ∠ACB+∠E=(1/3) ∠ACB+(180-(2/3) ∠ABC- (2/3) ∠ACB)=130
整理得：∠ACB+2∠ABC=150 ①
∠2=(1/3) ∠ABC+∠E=(1/3) ∠ABC+(180-(2/3) ∠ABC- (2/3) ∠ACB)=110
整理得：∠ABC+2∠ACB=210 ②
由方程①②解得：∠ACB=90，∠ABC=30
∴∠A=180-∠ACB-∠ABC=180-90-30=60
（2）∵∠2=∠1+（1/3）∠ABC=110+（1/3）∠ABC=130
∴∠ABC=60
∴∠EBC=20
∴∠DCB=180-20-130=30
∴∠ACB=60
∴∠A=180-60-60=60