数学
高一数学必修4P20的三角函数题用定义法、公式一以及计算器等求下列角的三个三角函数值:(1) -(17π)/3(2) 21π/4(3) -(23π)/6(4) 1500°

2020-01-04

高一数学必修4P20的三角函数题
用定义法、公式一以及计算器等求下列角的三个三角函数值:
(1) -(17π)/3
(2) 21π/4
(3) -(23π)/6
(4) 1500°
优质解答
-(17π)/3=6π-1/3πsin(-(17π)/3)=sin(6π-1/3π)=sin(-1/3π)=-根3/2同理:cos(-(17π)/3)=1/2 tan(-(17π)/3)=-根321π/4=6π-3/4πsin(21π/4)=sin(6π-3/4π)=sin(-3/4π)=-根2/2同理:cos(21π/4)=根2/2 tan(... -(17π)/3=6π-1/3πsin(-(17π)/3)=sin(6π-1/3π)=sin(-1/3π)=-根3/2同理:cos(-(17π)/3)=1/2 tan(-(17π)/3)=-根321π/4=6π-3/4πsin(21π/4)=sin(6π-3/4π)=sin(-3/4π)=-根2/2同理:cos(21π/4)=根2/2 tan(...
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