高一数学三角函数问题!急!急!sin（x+∏/3）=√3/2,求x的值
2019-05-02
高一数学三角函数问题!急!急!
sin（x+∏/3）=√3/2,求x的值
优质解答
sin(x+π/3)=sin(π/3)
sin(x+π/3)-sin(π/3)=0 ,由和差化积公式得：
2cos[(x+2π/3)/2]sin(x/2)=0
cos[(x+2π/3)/2]=0,或sin(x/2)=0
(x+2π/3)/2=π/2+kπ或x/2=kπ
x=π/3+2kπ或x=2kπ
sin(x+π/3)=sin(π/3)
sin(x+π/3)-sin(π/3)=0 ,由和差化积公式得：
2cos[(x+2π/3)/2]sin(x/2)=0
cos[(x+2π/3)/2]=0,或sin(x/2)=0
(x+2π/3)/2=π/2+kπ或x/2=kπ
x=π/3+2kπ或x=2kπ