用简便方法计算(3+1)(3^2+1)(3^4+1)(3^8+1)整式与代数式的题目.谢谢
2019-05-07
用简便方法计算(3+1)(3^2+1)(3^4+1)(3^8+1)
整式与代数式的题目.谢谢
优质解答
(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^4-1)(3^4+1)(3^8+1)/(3-1)
=(3^8-1)(3^8+1)/(3-1)
=(3^16-1)/2
=21523360
(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)/(3-1)
=(3^4-1)(3^4+1)(3^8+1)/(3-1)
=(3^8-1)(3^8+1)/(3-1)
=(3^16-1)/2
=21523360