数学
求极限limx(sqrt(x^2+100)+x) x趋向于负无穷

2019-06-02

求极限limx(sqrt(x^2+100)+x) x趋向于负无穷
优质解答
limx(sqrt(x^2+100)+x)
=lim100x/(sqrt(x^2+100)-x)
=lim100/(-sqrt(1+100/x^2)-1)
=-50
limx(sqrt(x^2+100)+x)
=lim100x/(sqrt(x^2+100)-x)
=lim100/(-sqrt(1+100/x^2)-1)
=-50
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