优质解答
(1):①2CH3OH(l)+3O2(g)⇌2CO2(g)+4H2O(g)△H=-1275.6kJ•mol-1②2CO(g)+O2(g)⇌2CO2(g)△H=-566.0kJ•mol-1③H2O(l)=H2O(g)△H=+44.0kJ•mol-1由盖斯定律计算,(①-②-③×4)12得到甲醇不完...
(1):①2CH3OH(l)+3O2(g)⇌2CO2(g)+4H2O(g)△H=-1275.6kJ•mol-1②2CO(g)+O2(g)⇌2CO2(g)△H=-566.0kJ•mol-1③H2O(l)=H2O(g)△H=+44.0kJ•mol-1由盖斯定律计算,(①-②-③×4)12得到甲醇不完...