数学
数学三角函数题1.将下列三角函数转化为锐角三角函数,并填在横线上:(1)cos210°= (2)sin263°42′= (3)cos(-π/6)= (4)sin(-5π/3) = (5)cos(-11π/9)= (6)cos(-104°26′)= (7)tan632°24′= (8)tan17π/6 = 2.用诱导公式求下列三角函数值:(1)cos(-17π/4) (2)sin(-1574°)(3)sin(-2160°52′) (4)cos(-1751°36′)(5)cos1615°8′ (6)si

2019-06-24

数学三角函数题
1.将下列三角函数转化为锐角三角函数,并填在横线上:
(1)cos210°= ______ (2)sin263°42′= ______
(3)cos(-π/6)= _____ (4)sin(-5π/3) = ______
(5)cos(-11π/9)=_____ (6)cos(-104°26′)= _____
(7)tan632°24′= _____ (8)tan17π/6 = _____
2.用诱导公式求下列三角函数值:
(1)cos(-17π/4) (2)sin(-1574°)
(3)sin(-2160°52′) (4)cos(-1751°36′)
(5)cos1615°8′ (6)sin(-26π/3)
优质解答
(1)cos210°= ___-cos30°___ (2)sin263°42′= __-sin83°42′____
(3)cos(-π/6)= __cosπ/6___ (4)sin(-5π/3) = __sinπ/3____
(5)cos(-11π/9)=__-cos(2π/9)___ (6)cos(-104°26′)= __-cos75°34′___
(7)tan632°24′= __-tan87°36′___ (8)tan17π/6 = __-tanπ/6___
2.用诱导公式求下列三角函数值:
(1)cos(-17π/4)
=cos(4π-17π/4)
=cos(-π/4)
=cosπ/4
=根号2/2
(2)sin(-1574°)
=sin(1800-1574)
=sin226
=sin(180+46)
=-sin46
(3)sin(-2160°52′)
=sin(2160-2160°52′
=sin(-52′)
=-sin52′
(4)cos(-1751°36′)
=cos(1800-1751°36′)
=cos48°24′
(5)cos1615°8′
=cos(1615°8′-1800)
=cos(-184°52′)
=-cos184°52′
=-cos(180+4°52′)
=cos4°52′
(6)sin(-26π/3)
=sin(8π-26π/3)
=sin(-2π/3)
=-sin2π/3
=-sinπ/3
=-根号3/2
(1)cos210°= ___-cos30°___ (2)sin263°42′= __-sin83°42′____
(3)cos(-π/6)= __cosπ/6___ (4)sin(-5π/3) = __sinπ/3____
(5)cos(-11π/9)=__-cos(2π/9)___ (6)cos(-104°26′)= __-cos75°34′___
(7)tan632°24′= __-tan87°36′___ (8)tan17π/6 = __-tanπ/6___
2.用诱导公式求下列三角函数值:
(1)cos(-17π/4)
=cos(4π-17π/4)
=cos(-π/4)
=cosπ/4
=根号2/2
(2)sin(-1574°)
=sin(1800-1574)
=sin226
=sin(180+46)
=-sin46
(3)sin(-2160°52′)
=sin(2160-2160°52′
=sin(-52′)
=-sin52′
(4)cos(-1751°36′)
=cos(1800-1751°36′)
=cos48°24′
(5)cos1615°8′
=cos(1615°8′-1800)
=cos(-184°52′)
=-cos184°52′
=-cos(180+4°52′)
=cos4°52′
(6)sin(-26π/3)
=sin(8π-26π/3)
=sin(-2π/3)
=-sin2π/3
=-sinπ/3
=-根号3/2
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