怎样用matlab求解复杂的微分方程组d2x/dt2=(x^2+3x)(dy/dt)d2y/dt2=-(x^2+3x)(dx/dt)当t=0时,x(0)=0,y(0)=0(dx/dt)(0)=a,(dy/dt)(0)=a(d2x/dt2)(0)=a,(d2y/dt2)(0)=a先要得到x,y分别关于t的表达式,然后得到y关于x的表达式初值条件应该是：当t=0时,x(0)=0,y(0)=0(dx/dt)(0)=a,(dy/dt)(0)=0(d2x/dt2)(0)=0,(d2y/dt2)(0)=b其中a,b为
2020-04-29
怎样用matlab求解复杂的微分方程组
d2x/dt2=(x^2+3x)(dy/dt)
d2y/dt2=-(x^2+3x)(dx/dt)
当t=0时,x(0)=0,y(0)=0
(dx/dt)(0)=a,(dy/dt)(0)=a
(d2x/dt2)(0)=a,(d2y/dt2)(0)=a
先要得到x,y分别关于t的表达式,
然后得到y关于x的表达式
初值条件应该是：
当t=0时,x(0)=0,y(0)=0
(dx/dt)(0)=a,(dy/dt)(0)=0
(d2x/dt2)(0)=0,(d2y/dt2)(0)=b
其中a,b为常数
优质解答
[x y]=dsolve('D2x=(x*x+3*x)*Dy','D2y=-(x*x+3*x)*Dx','x(0)=0','y(0)=0','Dx(0)=a','Dy(0)=a','D2x(0)=a','D2y(0)=a')%%%%%%%%%%%%%%%%%%%%%%%%%%%设定的X(1)=dx/dt;x(2)=x;x(3)=dy/dt;x(4)=y;%%%%%%%function dx=...
[x y]=dsolve('D2x=(x*x+3*x)*Dy','D2y=-(x*x+3*x)*Dx','x(0)=0','y(0)=0','Dx(0)=a','Dy(0)=a','D2x(0)=a','D2y(0)=a')%%%%%%%%%%%%%%%%%%%%%%%%%%%设定的X(1)=dx/dt;x(2)=x;x(3)=dy/dt;x(4)=y;%%%%%%%function dx=...