关于数学问题.因式分解,ab^2(x-y)^m+a^2b(x-y)^m+2==(m+2次方）(x+y)^2-(2x-y)^2==9(m+n)^2-4(m-n)^2==--=a^2b^2-m^n^2=x^2-(x+y-z)^2==-a+2a-a^3==a^3-2a(b+c)+(b+c)^2==谢谢啦.
2019-05-23
关于数学问题.
因式分解,
ab^2(x-y)^m+a^2b(x-y)^m+2=__________________=____________(m+2次方）
(x+y)^2-(2x-y)^2=______________=________________
9(m+n)^2-4(m-n)^2=_________=_____________--=______________
a^2b^2-m^n^2=________________
x^2-(x+y-z)^2=______________=________________
-a+2a-a^3=______________=_________________
a^3-2a(b+c)+(b+c)^2=_____________=_____________
谢谢啦.
优质解答
1.=ab(x-y)^m(b+a(x-y)^2)
2.=(x+y+2x-y)(x+y-2x+y)=3x（2y-x）
3.=(3m+3n)^-(2m-2n)^2=(3m+3n+2m-2n)(3m+3n-2m+2n)=(5m+n)(5n+m)
4.a^2b^2-m^n^2应该是a^2b^2-m^2n^2吧.如果是这样的话,=（ab+nm）(ab+mn)
5.(x+x+y-z)(x-x-y+z)=(2x+y-z)(-y+z)
6.a(1-a^2)=a(1+a)(1-a)
7.a^3-2a(b+c)+(b+c)^2应该是a^2-2a(b+c)+(b+c)^2吧.
=(a-(b+c))^2=(a-b-c)^2
1.=ab(x-y)^m(b+a(x-y)^2)
2.=(x+y+2x-y)(x+y-2x+y)=3x（2y-x）
3.=(3m+3n)^-(2m-2n)^2=(3m+3n+2m-2n)(3m+3n-2m+2n)=(5m+n)(5n+m)
4.a^2b^2-m^n^2应该是a^2b^2-m^2n^2吧.如果是这样的话,=（ab+nm）(ab+mn)
5.(x+x+y-z)(x-x-y+z)=(2x+y-z)(-y+z)
6.a(1-a^2)=a(1+a)(1-a)
7.a^3-2a(b+c)+(b+c)^2应该是a^2-2a(b+c)+(b+c)^2吧.
=(a-(b+c))^2=(a-b-c)^2