(2014•淄博一模)如图所示,曲线y=x2-1,x=2,x=0,y=0围成的阴影部分的面积为( )A.∫20|x2−1|dxB.|∫20(x2−1)dx|C.∫20(x2−1)dxD.∫10(x2−1)dx+∫21(1−x2)dx
2019-04-29
(2014•淄博一模)如图所示,曲线y=x2-1,x=2,x=0,y=0围成的阴影部分的面积为( )
A.|x2−1|dx
B.|(x2−1)dx|
C.(x2−1)dx
D.(x2−1)dx+(1−x2)dx
优质解答
由题意S=(1−x2)dx+(x2−1)dx=|x2−1|dx,
故选A.
由题意S=(1−x2)dx+(x2−1)dx=|x2−1|dx,
故选A.